JAMB 2012 · UTME · Q9

If PP is the set of all prime factors of 30 and QQ is the set of all factors of 18 less than 10, find P∩QP \cap Q.

Worked solution (try it first)
  1. 30=2×3×530 = 2 \times 3 \times 5, so P={2,3,5}P = \{2, 3, 5\}.
  2. The factors of 18 less than 10 are Q={1,2,3,6,9}Q = \{1, 2, 3, 6, 9\}.
  3. Both sets contain 2 and 3, so P∩Q={2,3}P \cap Q = \{2, 3\}, option B.

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