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JAMB 2013 · UTME · Q11

If S=t2−4t+4S = \sqrt{t^2 - 4t + 4}, find tt in terms of SS.

Worked solution (try it first)
  1. The expression under the root is a perfect square: t2−4t+4=(t−2)2t^2 - 4t + 4 = (t - 2)^2.
  2. So S=(t−2)2=t−2S = \sqrt{(t - 2)^2} = t - 2.
  3. Add 2 to both sides: t=S+2t = S + 2, option D.

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