JAMB 2013 · UTME · Q13

The remainder when $6p^3 - p^2 - 47p + 30$ is divided by $p - 3$ is

Worked solution (try it first)

By the remainder theorem, the remainder on dividing by $p - 3$ is the value at $p = 3$ .
$6(27) - 9 - 47(3) + 30$ , which is $162 - 9 - 141 + 30$ .
So the remainder is 42, option D.