JAMB 2013 · UTME · Q20✱

The $n$ th term of the progression $\frac42, \frac73, \frac{10}{4}, \frac{13}{5}, \ldots$ is

Worked solution (try it first)

Look at the tops and bottoms separately.
The tops $4, 7, 10, 13$ go up by 3, starting at 4, so they are $3n + 1$ .
The bottoms $2, 3, 4, 5$ are each one more than the term number, so they are $n + 1$ .
So the $n$ th term is $\dfrac{3n + 1}{n + 1}$ , option D.