JAMB 2013 · UTME · Q22

If P=(5321)P = \begin{pmatrix} 5 & 3 \\ 2 & 1 \end{pmatrix} and Q=(4235)Q = \begin{pmatrix} 4 & 2 \\ 3 & 5 \end{pmatrix}, find 2P+Q2P + Q.

Worked solution (try it first)
  1. Double every entry of PP: 2P=(10642)2P = \begin{pmatrix} 10 & 6 \\ 4 & 2 \end{pmatrix}.
  2. Add QQ entry by entry, in matching positions: (10+46+24+32+5)\begin{pmatrix} 10 + 4 & 6 + 2 \\ 4 + 3 & 2 + 5 \end{pmatrix}.
  3. So 2P+Q=(14877)2P + Q = \begin{pmatrix} 14 & 8 \\ 7 & 7 \end{pmatrix}, option D.

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