JAMB 2013 · UTME · Q31

If the midpoint of the line PQPQ is (2,3)(2, 3) and the point PP is (−2,1)(-2, 1), find the coordinates of QQ.

Worked solution (try it first)
  1. The midpoint is the average of the ends, so each coordinate of QQ is twice the midpoint's minus PP's.
  2. xx: 2(2)−(−2)=62(2) - (-2) = 6.
  3. yy: 2(3)−1=52(3) - 1 = 5.
  4. So Q=(6,5)Q = (6, 5), option D.

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