JAMB 2013 · UTME · Q45

If the variance of 3+x3 + x, 66, 44, xx and 7−x7 - x is 4 and the mean is 5, find the standard deviation.

Worked solution (try it first)
  1. The standard deviation is the square root of the variance, so it is 4=2\sqrt4 = 2, option D.
  2. As a check: the mean is 20+x5=5\frac{20 + x}{5} = 5, so x=5x = 5.
  3. The numbers are 8, 6, 4, 5, 2, whose squared deviations 9, 1, 1, 0, 9 add up to 20, and 205=4\frac{20}{5} = 4.

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