JAMB 2013 · UTME · Q47

In how many ways can a student select 2 subjects from 5 subjects?

Worked solution (try it first)
  1. The order of the two subjects doesn't matter, so this is 5C2^5C_2.
  2. nCr=n!r! (n−r)!^nC_r = \dfrac{n!}{r!\,(n - r)!}, so 5C2=5!2! 3!^5C_2 = \dfrac{5!}{2!\,3!}, option A.

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