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JAMB 2013 · UTME · Q49

What is the probability that an integer xx (1≤x≤251 \le x \le 25) chosen at random is divisible by both 2 and 3?

Worked solution (try it first)
  1. Divisible by both 2 and 3 means divisible by 6.
  2. The multiples of 6 up to 25 are 6, 12, 18, 24, which is 4 numbers.
  3. So the probability is 425\frac{4}{25}, option A.

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