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JAMB 2014 · UTME · Q6

If log⁡7.5=0.8751\log 7.5 = 0.8751, evaluate 2log⁡75+log⁡7502\log 75 + \log 750.

Worked solution (try it first)
  1. 75=7.5×1075 = 7.5 \times 10, so log⁡75=1+0.8751=1.8751\log 75 = 1 + 0.8751 = 1.8751.
  2. In the same way, log⁡750=2+0.8751=2.8751\log 750 = 2 + 0.8751 = 2.8751.
  3. 2log⁡75=2×1.8751=3.75022\log 75 = 2 \times 1.8751 = 3.7502.
  4. So the value is 3.7502+2.8751=6.62533.7502 + 2.8751 = 6.6253, option C.

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