JAMB 2014 · UTME · Q9

Evaluate log⁡28+log⁡216−log⁡24\log_2 8 + \log_2 16 - \log_2 4.

Worked solution (try it first)
  1. 23=82^3 = 8, 24=162^4 = 16 and 22=42^2 = 4, so the logs are 3, 4 and 2.
  2. So the value is 3+4−2=53 + 4 - 2 = 5, option D.

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