JAMB 2014 · UTME · Q9LogarithmsEvaluate log28+log216−log24\log_2 8 + \log_2 16 - \log_2 4log28+log216−log24.A6B3C4D5Worked solution (try it first)23=82^3 = 823=8, 24=162^4 = 1624=16 and 22=42^2 = 422=4, so the logs are 3, 4 and 2.So the value is 3+4−2=53 + 4 - 2 = 53+4−2=5, option D.Report a problem with this question