JAMB 2015 · UTME · Q1

The sum of the progression 1+x+x2+…1 + x + x^2 + \ldots (where ∣x∣<1|x| < 1) is

Worked solution (try it first)
  1. This is a G.P. with first term a=1a = 1 and common ratio r=xr = x.
  2. Since ∣x∣<1|x| < 1, the sum to infinity exists: S∞=a1−rS_\infty = \dfrac{a}{1 - r}.
  3. So the sum is 11−x\dfrac{1}{1 - x}, option A.

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