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JAMB 2016 · UTME · Q28

Divide 2x3+11x2+17x+62x^3 + 11x^2 + 17x + 6 by 2x+12x + 1.

Worked solution (try it first)
  1. Long division: 2x3÷2x=x22x^3 \div 2x = x^2.
  2. Subtract x2(2x+1)=2x3+x2x^2(2x + 1) = 2x^3 + x^2 to leave 10x2+17x+610x^2 + 17x + 6.
  3. 10x2÷2x=5x10x^2 \div 2x = 5x.
  4. Subtract 5x(2x+1)=10x2+5x5x(2x + 1) = 10x^2 + 5x to leave 12x+612x + 6.
  5. 12x÷2x=612x \div 2x = 6, and 6(2x+1)=12x+66(2x + 1) = 12x + 6 leaves 0.
  6. So the quotient is x2+5x+6x^2 + 5x + 6, option A.

Also set as JAMB 1998 · UME · Q15

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