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JAMB 2016 · UTME · Q33

0.00014321940000=k×10n\dfrac{0.0001432}{1940000} = k \times 10^n, where 1≤k<101 \le k < 10 and nn is a whole number. The values of kk and nn are

Worked solution (try it first)
  1. Write both in standard form: 0.0001432=1.432×10−40.0001432 = 1.432 \times 10^{-4} and 1 940 000=1.94×1061\,940\,000 = 1.94 \times 10^6.
  2. Divide the numbers, 1.432÷1.94=0.73811.432 \div 1.94 = 0.7381, and subtract the powers, 10−4−6=10−1010^{-4 - 6} = 10^{-10}.
  3. 0.7381×10−10=7.381×10−110.7381 \times 10^{-10} = 7.381 \times 10^{-11}, so k=7.381k = 7.381 and n=−11n = -11, option A.

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