JAMB 2016 · UTME · Q36

If 2x+3y=12x + 3y = 1 and x−2y=11x - 2y = 11, find (x+y)(x + y).

Worked solution (try it first)
  1. Make xx the subject of the second equation: x=11+2yx = 11 + 2y.
  2. Substitute into the first: 2(11+2y)+3y=12(11 + 2y) + 3y = 1, so 22+7y=122 + 7y = 1 and y=−3y = -3.
  3. Then x=11−6=5x = 11 - 6 = 5.
  4. So x+y=5+(−3)=2x + y = 5 + (-3) = 2, option D.

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