JAMB 2016 · UTME · Q9✱✱

The gradient of a curve is 2x+72x + 7 and the curve passes through the point (2,0)(2, 0). Find the equation of the curve.

Worked solution (try it first)
  1. Integrate the gradient to get the curve: y=x2+7x+cy = x^2 + 7x + c.
  2. The curve passes through (2,0)(2, 0), so put in x=2x = 2 and y=0y = 0: 0=4+14+c0 = 4 + 14 + c.
  3. So c=−18c = -18 and the curve is y=x2+7x−18y = x^2 + 7x - 18, option B.

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