JAMB 2017 · UTME · Q20

What is the probability that an integer xx, 1≤x≤201 \le x \le 20, chosen at random is divisible by both 2 and 3?

Worked solution (try it first)
  1. Divisible by both 2 and 3 means divisible by 6.
  2. The multiples of 6 up to 20 are 6, 12, 18, which is 3 numbers.
  3. So the probability is 320\frac{3}{20}, option C.

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