JAMB 2017 · UTME (set 2) · Q1

Given T={even numbers from 1 to 12}T = \{\text{even numbers from 1 to 12}\} and N={common factors of 6, 8 and 12}N = \{\text{common factors of 6, 8 and 12}\}, find T∩NT \cap N.

Worked solution (try it first)
  1. T={2,4,6,8,10,12}T = \{2, 4, 6, 8, 10, 12\}.
  2. The factors of 6 are 1, 2, 3, 6.
  3. Of 8 are 1, 2, 4, 8.
  4. Of 12 are 1, 2, 3, 4, 6, 12.
  5. Common to all three: N={1,2}N = \{1, 2\}.
  6. So T∩N={2}T \cap N = \{2\}, option D.

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