QuestionJAMBGeneral Maths2017ObjectiveIndices & standard formIndices & standard form
JAMB 2017 · UTME (set 2) · Q11
Simplify 81n3n−1×27n+1.
Worked solution (try it first)
Write everything as a power of 3:
27n+1=33n+3 and
81n=34n.
Top: add the indices,
(n−1)+(3n+3)=4n+2, so the top is
34n+2.
Divide: subtract the indices,
(4n+2)−4n=2.
So the value is
32=9, option B.
Report a problem with this question