JAMB 2017 · UTME (set 2) · Q18

Simplify 427+512−3754\sqrt{27} + 5\sqrt{12} - 3\sqrt{75}.

Worked solution (try it first)
  1. Take out square factors: 427=4×334\sqrt{27} = 4 \times 3\sqrt3, which is 12312\sqrt3.
  2. Likewise 512=5×23=1035\sqrt{12} = 5 \times 2\sqrt3 = 10\sqrt3 and 375=3×53=1533\sqrt{75} = 3 \times 5\sqrt3 = 15\sqrt3.
  3. Combine: 123+103−153=7312\sqrt3 + 10\sqrt3 - 15\sqrt3 = 7\sqrt3, option D.

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