JAMB 2017 · UTME (set 2) · Q45✱✱

In how many ways can the letters of the word ACCEPTANCE be arranged?

Worked solution (try it first)

ACCEPTANCE has 10 letters: C appears 3 times, A twice and E twice.
P, T and N appear once.
Divide $10!$ by the factorial of each repeat count, so that swapping identical letters is not counted as new.
So the number of arrangements is $\dfrac{10!}{3!\,2!\,2!}$ , option D.