JAMB 2018 · UTME · Q34Calculus (JAMB bridge)Evaluate ∫−π/2π/2cosx dx\displaystyle\int_{-\pi/2}^{\pi/2} \cos x\,dx∫−π/2π/2cosxdx.A0B1C2D3Worked solution (try it first)cosx\cos xcosx integrates to sinx\sin xsinx.[sinx]−π/2π/2=sinπ2−sin(−π2)\left[\sin x\right]_{-\pi/2}^{\pi/2} = \sin\frac\pi2 - \sin\left(-\frac\pi2\right)[sinx]−π/2π/2=sin2π−sin(−2π)=1−(−1)= 1 - (-1)=1−(−1)=2= 2=2, option C.Report a problem with this question