NECO 2023 · Paper 1 · Q18

Find the first 4 terms in the expansion of (1+2x)15(1 + 2x)^{15}.

Worked solution (try it first)
  1. Each term is (15r)(2x)r\binom{15}{r}(2x)^r.
  2. The coefficients needed are (151)=15\binom{15}{1} = 15, (152)=105\binom{15}{2} = 105 and (153)=455\binom{15}{3} = 455.
  3. r=1r = 1: 15×2x=30x15 \times 2x = 30x.
  4. r=2r = 2: 105×4x2=420x2105 \times 4x^2 = 420x^2.
  5. r=3r = 3: 455×8x3=3640x3455 \times 8x^3 = 3640x^3.
  6. So the first four terms are 1+30x+420x2+3640x31 + 30x + 420x^2 + 3640x^3, option C.

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