QuestionNECOFurther Maths2023ObjectiveSequences, series & binomial expansionSequences, series & binomial expansion
NECO 2023 · Paper 1 · Q18
Find the first 4 terms in the expansion of (1+2x)15.
Worked solution (try it first)
Each term is
(r15)(2x)r.
The coefficients needed are
(115)=15,
(215)=105 and
(315)=455.
r=1:
15×2x=30x.
r=2:
105×4x2=420x2.
r=3:
455×8x3=3640x3.
So the first four terms are
1+30x+420x2+3640x3, option C.
Report a problem with this question