NECO 2023 · Paper 1 · Q25

Find the values of xx for which g(x)=x2−5x+6x2−5x−24g(x) = \dfrac{x^2 - 5x + 6}{x^2 - 5x - 24} is undefined.

Worked solution (try it first)
  1. A fraction is undefined where its bottom is zero: x2−5x−24=0x^2 - 5x - 24 = 0.
  2. Two numbers that multiply to −24-24 and add to −5-5 are −8-8 and 3, so (x−8)(x+3)=0(x - 8)(x + 3) = 0.
  3. So x=8x = 8 or x=−3x = -3, option B.

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