NECO 2023 · Paper 1 · Q39

A horizontal force of 3500 N is capable of moving an abandoned vehicle of mass 750 kg on a rough horizontal road. Find the coefficient of friction between the vehicle and the road. [Take g=9.8 ms−2g = 9.8\text{ ms}^{-2}]

Worked solution (try it first)
  1. On a horizontal road the normal reaction equals the weight: R=mg=750×9.8R = mg = 750 \times 9.8, which is 7350 N.
  2. The force just moves the vehicle, so friction is limiting: μR=3500\mu R = 3500.
  3. So μ=35007350≈0.48\mu = \dfrac{3500}{7350} \approx 0.48, option C.

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