NECO 2023 · Paper 2 · Q6

The table shows the distribution of marks obtained by 100 candidates in an examination. Calculate, correct to three significant figures, the standard deviation.

Marks 1–10 11–20 21–30 31–40 41–50
Frequency 9 49 32 8 2
Worked solution (try it first)
  1. Class marks: 5.5,15.5,25.5,35.5,45.55.5, 15.5, 25.5, 35.5, 45.5.
  2. Take A=25.5A = 25.5, so d=−20,−10,0,10,20d = -20, -10, 0, 10, 20.
  3. ∑fd=9(−20)+49(−10)+0+8(10)+2(20)\sum fd = 9(-20) + 49(-10) + 0 + 8(10) + 2(20)
    =−550= -550.
  4. ∑fd2=9(400)+49(100)+0+8(100)+2(400)\sum fd^2 = 9(400) + 49(100) + 0 + 8(100) + 2(400)
    =10 100= 10\,100.
  5. σ=10 100100−(−550100)2\sigma = \sqrt{\dfrac{10\,100}{100} - \left(\dfrac{-550}{100}\right)^2}
    =101−30.25= \sqrt{101 - 30.25}
    =70.75= \sqrt{70.75}
    ≈8.41\approx 8.41.

Report a problem with this question