NECO 2022 · Paper 1 · Q36

In an isosceles triangle MNOMNO, where MN‾=MO‾=6\overline{MN} = \overline{MO} = 6 cm and ∠NMO=112∘\angle NMO = 112^\circ, calculate NO‾\overline{NO}, correct to 2 significant figures.

Worked solution (try it first)
  1. Use the cosine rule: NO2=62+62−2(6)(6)cos⁡112∘NO^2 = 6^2 + 6^2 - 2(6)(6)\cos 112^\circ.
  2. cos⁡112∘≈−0.3746\cos 112^\circ \approx -0.3746, so NO2≈72+26.97=98.97NO^2 \approx 72 + 26.97 = 98.97.
  3. NO≈9.948NO \approx 9.948 cm, which is 9.9 cm to 2 significant figures, option B.

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