NECO 2022 · Paper 1 · Q39

Find the equation of a straight line passing through the point (−1,4)(-1, 4) and parallel to the line y=3x+2y = 3x + 2.

Worked solution (try it first)
  1. Parallel lines have the same gradient, so m=3m = 3.
  2. Use y−y1=m(x−x1)y - y_1 = m(x - x_1): y−4=3(x+1)y - 4 = 3(x + 1).
  3. Expand: y=3x+7y = 3x + 7, so y−3x=7y - 3x = 7, option B.

Report a problem with this question