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NECO 2022 · Paper 1 · Q4

If 3(6−9x)=27(1−2x)3^{(6 - 9x)} = 27^{(1 - 2x)}, find the value of xx.

Worked solution (try it first)
  1. Write 27 as 333^3, so the right side is 33(1−2x)=33−6x3^{3(1 - 2x)} = 3^{3 - 6x}.
  2. The bases are equal, so the powers are equal: 6−9x=3−6x6 - 9x = 3 - 6x.
  3. Collect terms: 3=3x3 = 3x, so x=1x = 1, option C.

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