NECO 2022 · Paper 2 · Q12

The pie chart below shows the sectorial allocation of subjects offered by 720 students in a college.

Econs (4x + 3y)Civic Edu. 10yMaths (3x + 5y)Eng. 5x
Sector angles are in degrees; the Econs sector is marked as a right angle.
  1. (i)

    Determine the values of xx and yy.

    Separate values with commas, e.g. 3, −2

  2. (ii)

    What percentage of the students offered Maths, correct to 1 decimal place?

  3. (iii)

    If a student is picked at random, find the probability that the student offered either Econs or Civic Edu.

Worked solution (try it first)

(i)

  1. The Econs sector is marked as a right angle, so 4x+3y=904x + 3y = 90 (1).
  2. The angles at the centre add up to 360∘360^\circ: (4x+3y)+5x+(3x+5y)+10y=360(4x + 3y) + 5x + (3x + 5y) + 10y = 360.
  3. Collect like terms: 12x+18y=36012x + 18y = 360.
  4. Divide by 6: 2x+3y=602x + 3y = 60 (2).
  5. Subtract (2) from (1): 2x=302x = 30, so x=15x = 15.
  6. Put x=15x = 15 into (2): 30+3y=6030 + 3y = 60, so y=10y = 10.
  7. The sector angles are Econs 90∘90^\circ, Eng.
  8. 75∘75^\circ, Maths 95∘95^\circ and Civic Edu.
  9. 100∘100^\circ, which add up to 360∘360^\circ.

(ii)

  1. Maths has 3(15)+5(10)=95∘3(15) + 5(10) = 95^\circ.
  2. As a percentage: 95360×100=26.38…\frac{95}{360} \times 100 = 26.38\ldots, so 26.4%26.4\% of the students offered Maths.

(iii)

  1. The events are exclusive, so add the angles: Econs and Civic Edu. together take 90∘+100∘=190∘90^\circ + 100^\circ = 190^\circ.
  2. The probability is 190360=1936\frac{190}{360} = \frac{19}{36}.

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