NECO 2023 · Paper 1 · Q35

In the diagram, OO is the centre of the circle PQRPQR. If ∠QPR=64∘\angle QPR = 64^\circ and ∠QRP=46∘\angle QRP = 46^\circ, calculate ∠POQ\angle POQ.

64°46°OPQR
Worked solution (try it first)
  1. ∠POQ\angle POQ is at the centre on arc PQPQ.
  2. The angle at the circumference on the same arc is at RR: ∠PRQ=46∘\angle PRQ = 46^\circ.
  3. The angle at the centre is twice the angle at the circumference: ∠POQ=2×46∘=92∘\angle POQ = 2 \times 46^\circ = 92^\circ, option C.

Report a problem with this question