An aeroplane flies from a town P on a bearing of 045∘ to a town Q, a distance of 200 km. It then changes course and flies to another town R on a bearing of 120∘. If R is directly east of P, calculate ∣PR∣, correct to the nearest km.
Worked solution (try it first)
On 045∘, Q is 200sin45∘≈141.4 km east and 200cos45∘≈141.4 km north of P.
R is due east of P, so the second leg must come back 141.4 km south.
The bearing 120∘ is 60∘ from due south, so QRcos60∘=141.4, giving QR≈282.8 km.