NECO 2024 · Paper 1 · Q18

Logarithms

Evaluate $\log_4 16 + \log_3 27 - \log_8 4096$ .

Worked solution (try it first)

$4^2 = 16$ , so $\log_4 16 = 2$ .
And $3^3 = 27$ , so $\log_3 27 = 3$ .
$8^4 = 4096$ , so $\log_8 4096 = 4$ .
So the value is $2 + 3 - 4 = 1$ , option C.

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