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NECO 2024 · Paper 1 · Q2

If A={natural numbers between 3 and 15}A = \{\text{natural numbers between 3 and 15}\}, find n(A)n(A).

Worked solution (try it first)
  1. "Between 3 and 15" leaves out 3 and 15, so A={4,5,6,…,14}A = \{4, 5, 6, \dots, 14\}.
  2. Count them: 14−4+1=1114 - 4 + 1 = 11, so n(A)=11n(A) = 11, option D.

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