NECO 2024 · Paper 1 · Q37

A boy walks 4 km4\text{ km} due west. He then changes direction and walks on a bearing of 214∘214^\circ until he is south-west of his starting point. How far is he from his starting point? Correct your answer to one decimal place.

Worked solution (try it first)
  1. Put the start at the origin.
  2. After the first leg he is at (−4,0)(-4, 0).
  3. On 214∘214^\circ (that is, 34∘34^\circ west of south), walking tt km adds (−tsin⁡34∘,−tcos⁡34∘)(-t\sin34^\circ, -t\cos34^\circ).
  4. South-west of the start means as far south as west: 4+0.5592t=0.8290t4 + 0.5592t = 0.8290t, so t≈14.83t \approx 14.83 km.
  5. He is then about 12.29 km west and 12.29 km south, so his distance is 12.292≈17.412.29\sqrt2 \approx 17.4 km, option E.

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