NECO 2024 · Paper 1 · Q43

Find the distance between the points (3,−4)(3, -4) and (−5,2)(-5, 2).

Worked solution (try it first)
  1. The changes are −5−3=−8-5 - 3 = -8 in xx and 2−(−4)=62 - (-4) = 6 in yy.
  2. By Pythagoras the distance is 82+62=100=10\sqrt{8^2 + 6^2} = \sqrt{100} = 10, option E.

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