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NECO 2024 · Paper 1 · Q59

A particle moves a distance of SS metres in tt seconds, where S=5t3−12t2+7S = 5t^3 - 12t^2 + 7. Find the velocity after 3 seconds.

Worked solution (try it first)
  1. Velocity is v=dSdt=15t2−24tv = \frac{dS}{dt} = 15t^2 - 24t.
  2. At t=3t = 3: 15×9−24×3=135−72=6315 \times 9 - 24 \times 3 = 135 - 72 = 63 m/s, option B.

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