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NECO 2024 · Paper 1 · Q7

A wire of length 25 cm25\text{ cm} was measured by a student to be 24.4 cm24.4\text{ cm}. Find the percentage error.

Worked solution (try it first)
  1. The error is 25−24.4=0.625 - 24.4 = 0.6 cm.
  2. Divide by the true length and multiply by 100: 0.625×100%=0.024×100%\frac{0.6}{25} \times 100\% = 0.024 \times 100\%.
  3. So the percentage error is 2.4%, option C.

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