NECO 2024 · Paper 2 · Q4

Given the numbers 2, 6, 9, 8, 7, 9, 8, 7, calculate, correct to 2 decimal places, the:

  1. (i)

    mean deviation;

  2. (ii)

    standard deviation.

Worked solution (try it first)
  1. First the mean: 2+6+9+8+7+9+8+7=562 + 6 + 9 + 8 + 7 + 9 + 8 + 7 = 56, and there are 8 numbers, so xˉ=568=7\bar x = \frac{56}{8} = 7.

(i)

  1. The distances from 7, ignoring signs, are ∣x−7∣=5,1,2,1,0,2,1,0|x - 7| = 5, 1, 2, 1, 0, 2, 1, 0, which add up to 12.
  2. Mean deviation =128=1.50= \frac{12}{8} = 1.50.

(ii)

  1. Square each deviation: (x−7)2=25,1,4,1,0,4,1,0(x - 7)^2 = 25, 1, 4, 1, 0, 4, 1, 0, which add up to 36.
  2. Variance =368=4.5= \frac{36}{8} = 4.5, so the standard deviation is 4.5≈2.12\sqrt{4.5} \approx 2.12.

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