NECO 2024 · Paper 2 · Q7

  1. (a)

    Solve the equation 1912−34(x−4)=56\dfrac{19}{12} - \dfrac{3}{4(x - 4)} = \dfrac56.

  2. (b)

    The cost of transportation is partly constant and partly varies as the distance covered. The cost is ₦1,025.00 when 220 km is covered and ₦1,345.00 when 300 km is covered. If the distance between Lagos and Kaduna is 982 km, find the cost of transportation (₦).

Worked solution (try it first)

(a)

  1. Move the known fractions to one side: 34(x−4)=1912−56\frac{3}{4(x - 4)} = \frac{19}{12} - \frac56.
  2. With denominator 12, 56=1012\frac56 = \frac{10}{12}, so the right side is 912=34\frac{9}{12} = \frac34.
  3. Now 34(x−4)=34\frac{3}{4(x - 4)} = \frac34.
  4. The tops are both 3, so the bottoms must be equal: 4(x−4)=44(x - 4) = 4.
  5. So x−4=1x - 4 = 1 and x=5x = 5.

(b)

  1. "Partly constant and partly varies as the distance" means C=a+bdC = a + bd, where CC is the cost in naira and dd the distance in km.
  2. From the two journeys: a+220b=1025a + 220b = 1025 and a+300b=1345a + 300b = 1345.
  3. Take the first from the second: 80b=32080b = 320, so b=4b = 4.
  4. Then a=1025−220×4=145a = 1025 - 220 \times 4 = 145.
  5. So C=145+4dC = 145 + 4d.
  6. For 982 km: C=145+4×982C = 145 + 4 \times 982
    =145+3928= 145 + 3928
    =4073= 4073.
  7. The cost is ₦4,073.00.

Report a problem with this question