WAEC 2008 · Paper 2 · Q13

The table shows the examination marks of 8 students in Algebra and Statistics tests.

Algebra (xx) 10 24 30 35 48 59 68 70
Statistics (yy) 30 47 44 71 60 89 97 74
  1. (a)

    Draw a scatter diagram for the data.

    Model answer
    102030405060708020406080100Algebra (x)Statistics (y)

    Put Algebra (xx) on the horizontal axis and Statistics (yy) on the vertical axis, with a uniform scale on each, and plot the 8 points (10,30),(24,47),…,(70,74)(10, 30), (24, 47), \ldots, (70, 74).

  2. (b)

    Find xˉ\bar x, the mean of xx, and yˉ\bar y, the mean of yy, and plot (xˉ,yˉ)(\bar x, \bar y) on the graph.

    Separate values with commas, e.g. 3, −2

  3. (c)

    Draw a line of best fit to pass through (xˉ,yˉ)(\bar x, \bar y).

    Model answer
    102030405060708020406080100Algebra (x)Statistics (y)(43, 64)

    Draw a straight line through (43,64)(43, 64) that follows the trend of the points, with about as many points above it as below. A good line has a gradient near 0.940.94.

  4. (d)(i)

    From your graph, find the equation of the line.

    Model answer

    Read two points on your line, such as (43,64)(43, 64) and (78,97)(78, 97), find the gradient mm, then use y−64=m(x−43)y - 64 = m(x - 43). The least-squares line is y≈0.94x+23.5y \approx 0.94x + 23.5; a line drawn by eye will be close to this.

  5. (d)(ii)

    From your graph, estimate the Statistics mark for a student who scored 50 in Algebra.

Worked solution (try it first)

(a)

  1. Plot the 8 points with xx (Algebra) across and yy (Statistics) up.

(b)

  1. ∑x=10+24+30+35+48+59+68+70\sum x = 10 + 24 + 30 + 35 + 48 + 59 + 68 + 70
    =344= 344, so xˉ=3448=43\bar x = \frac{344}{8} = 43.
  2. ∑y=30+47+44+71+60+89+97+74\sum y = 30 + 47 + 44 + 71 + 60 + 89 + 97 + 74
    =512= 512, so yˉ=5128=64\bar y = \frac{512}{8} = 64.
  3. Plot (43,64)(43, 64).

(c)

  1. Draw a straight line through (43,64)(43, 64) that follows the trend, with the points spread evenly on both sides.

(d)(i)

  1. Read a second point on the line, for example (78,97)(78, 97).
  2. Gradient =97−6478−43= \frac{97 - 64}{78 - 43}
    =3335= \frac{33}{35}
    ≈0.94\approx 0.94.
  3. Use y−64=0.94(x−43)y - 64 = 0.94(x - 43): the line is about y=0.94x+23.5y = 0.94x + 23.5.

(ii)

  1. Read up from x=50x = 50 to the line and across: y≈0.94(50)+23.5≈71y \approx 0.94(50) + 23.5 \approx 71.
  2. The Statistics mark is about 71.

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