WAEC 2011 · Paper 2 · Q14

The number of cars that called at a petrol station on some days of a month is as shown in the table.

Days of the month (xx) 3 5 8 12 15 19 22 26
Number of cars (yy) 143 95 112 110 104 86 78 69
  1. (a)

    Represent this information on a scatter diagram.

    Model answer
    5101520253020406080100120140160Day (x)Number of cars (y)(13.75, 99.625)

    Plot the eight points (day across, number of cars up); don't join them. The means are xˉ=13.75\bar x = 13.75 and yˉ=99.625\bar y = 99.625: mark (13.75,99.625)(13.75, 99.625) and draw one straight line through it that follows the downward trend, with about as many points above it as below.

    For (c), read from the line: 80 cars at about day 22, and about 73 cars on day 25. Readings vary a little with the line you draw.

  2. (b)

    Draw the line of best fit to pass through the point (xˉ,yˉ)(\bar x, \bar y) where xˉ\bar x is the mean of xx and yˉ\bar y is the mean of yy.

    Separate values with commas, e.g. 3, −2

  3. (c)

    Use your diagram to estimate: (i) the day 80 cars called at the station; (ii) how many cars a petrol attendant at the station should expect on the 25th day.

    Separate values with commas, e.g. 3, −2

Try it on a graph

The scatter diagram; draw a line through the mean point.

Worked solution (try it first)

(a)

  1. Plot the eight points (3,143),(5,95),…,(26,69)(3, 143), (5, 95), \ldots, (26, 69).

(b)

  1. xˉ=1108=13.75\bar x = \dfrac{110}{8} = 13.75 and yˉ=7978=99.625\bar y = \dfrac{797}{8} = 99.625.
  2. Draw the line of best fit through (13.75,99.6)(13.75, 99.6), following the downward trend of the points.

(c)(i)

  1. Read across from y=80y = 80 to the line and down: about day 22.

(ii)

  1. Read up from x=25x = 25 to the line and across: about 73 cars.

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