WAEC 2014 · Paper 2 · Q7

  1. (a)

    If the position vectors of AA and BB relative to the origin are (43)\begin{pmatrix} 4 \\ 3 \end{pmatrix} and (5−2)\begin{pmatrix} 5 \\ -2 \end{pmatrix}, find the angle between OA→\overrightarrow{OA} and OB→\overrightarrow{OB}.

Worked solution (try it first)
  1. OA→⋅OB→=(4)(5)+(3)(−2)\overrightarrow{OA} \cdot \overrightarrow{OB} = (4)(5) + (3)(-2)
    =20−6= 20 - 6
    =14= 14.
  2. ∣OA→∣=5|\overrightarrow{OA}| = 5 and ∣OB→∣=29|\overrightarrow{OB}| = \sqrt{29}.
  3. cos⁡θ=14529\cos\theta = \dfrac{14}{5\sqrt{29}}
    ≈0.5200\approx 0.5200, so θ≈58.67∘\theta \approx 58.67^\circ.

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