WAEC 2017 · Paper 2 · Q8Vectors(a)Given that m=(−125)\mathbf m = \begin{pmatrix} -12 \\ 5 \end{pmatrix}m=(−125) and n=(1−1)\mathbf n = \begin{pmatrix} 1 \\ -1 \end{pmatrix}n=(1−1), find a vector p\mathbf pp such that ∣p∣=35|\mathbf p| = 35∣p∣=35 and p\mathbf pp is in the direction of m−5n\mathbf m - 5\mathbf nm−5n.CheckSeparate values with commas, e.g. 3, −2Worked solution (try it first)m−5n=(−12−55+5)\mathbf m - 5\mathbf n = \begin{pmatrix} -12 - 5 \\ 5 + 5 \end{pmatrix}m−5n=(−12−55+5)=(−1710)= \begin{pmatrix} -17 \\ 10 \end{pmatrix}=(−1710).Its length is 289+100=389\sqrt{289 + 100} = \sqrt{389}289+100=389.p=35389(−1710)\mathbf p = \dfrac{35}{\sqrt{389}}\begin{pmatrix} -17 \\ 10 \end{pmatrix}p=38935(−1710)≈(−30.1717.75)\approx \begin{pmatrix} -30.17 \\ 17.75 \end{pmatrix}≈(−30.1717.75).Report a problem with this question