WAEC 2017 · Paper 2 · Q8

  1. (a)

    Given that m=(−125)\mathbf m = \begin{pmatrix} -12 \\ 5 \end{pmatrix} and n=(1−1)\mathbf n = \begin{pmatrix} 1 \\ -1 \end{pmatrix}, find a vector p\mathbf p such that ∣p∣=35|\mathbf p| = 35 and p\mathbf p is in the direction of m−5n\mathbf m - 5\mathbf n.

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)
  1. m−5n=(−12−55+5)\mathbf m - 5\mathbf n = \begin{pmatrix} -12 - 5 \\ 5 + 5 \end{pmatrix}
    =(−1710)= \begin{pmatrix} -17 \\ 10 \end{pmatrix}.
  2. Its length is 289+100=389\sqrt{289 + 100} = \sqrt{389}.
  3. p=35389(−1710)\mathbf p = \dfrac{35}{\sqrt{389}}\begin{pmatrix} -17 \\ 10 \end{pmatrix}
    ≈(−30.1717.75)\approx \begin{pmatrix} -30.17 \\ 17.75 \end{pmatrix}.

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