WAEC 2018 · Paper 2 · Q9

  1. (a)

    The radius of a sphere increased by 212%2\frac12\%. Find the percentage increase in the volume.

  2. (b)

    If the coefficients of x2x^2 and x3x^3 in the binomial expansion of (p+qx)7(p + qx)^7 are equal, express qq in terms of pp.

Worked solution (try it first)

(a)

  1. V=43πr3V = \frac43\pi r^3, so for a small change δVV≈3δrr\dfrac{\delta V}{V} \approx 3\dfrac{\delta r}{r}.
  2. With δrr=212%\dfrac{\delta r}{r} = 2\frac12\%: δVV≈3×212%\dfrac{\delta V}{V} \approx 3 \times 2\frac12\%
    =712%= 7\frac12\%.
  3. (Exactly, 1.0253=1.07691.025^3 = 1.0769, an increase of about 7.69%7.69\%.)

(b)

  1. The x2x^2 term of (p+qx)7(p + qx)^7 is 21p5q2x221p^5q^2x^2 and the x3x^3 term is 35p4q3x335p^4q^3x^3.
  2. Set the coefficients equal: 21p5q2=35p4q321p^5q^2 = 35p^4q^3.
  3. Divide by 7p4q27p^4q^2: 3p=5q3p = 5q, so q=35pq = \frac35p.

Report a problem with this question