Past papers › WAEC · 2018 · Private, 2nd series · Further Maths · Paper 2 › Question 13 Question WAEC Further Maths 2018 Theory Probability & distributions Probability & distributions
WAEC 2018 · Paper 2 · Q13 One out of every 3 bolts produced by a machine is defective. If 4 of the bolts produced by the machine are selected at random, find the probability that:
(a) (b) (c) Worked solution (try it first) X ∼ B ( 4 , 1 3 ) X \sim B\left(4, \frac13\right) X ∼ B ( 4 , 3 1 ) , with
q = 2 3 q = \frac23 q = 3 2 .
(a) = ( 4 2 ) ( 1 3 ) 2 ( 2 3 ) 2 = \binom42\left(\frac13\right)^2\left(\frac23\right)^2 = ( 2 4 ) ( 3 1 ) 2 ( 3 2 ) 2 = 24 81 = \dfrac{24}{81} = 81 24 = 8 27 = \dfrac{8}{27} = 27 8 .
(b) At least 1:
1 − ( 2 3 ) 4 = 1 − 16 81 1 - \left(\frac23\right)^4 = 1 - \dfrac{16}{81} 1 − ( 3 2 ) 4 = 1 − 81 16 = 65 81 = \dfrac{65}{81} = 81 65 .
(c) At most 2:
P ( 0 ) + P ( 1 ) + P ( 2 ) = 16 + 32 + 24 81 P(0) + P(1) + P(2) = \dfrac{16 + 32 + 24}{81} P ( 0 ) + P ( 1 ) + P ( 2 ) = 81 16 + 32 + 24 = 72 81 = \dfrac{72}{81} = 81 72 Watch out
"At least 1" is quickest as 1 − P ( 0 ) 1 - P(0) 1 − P ( 0 ) . Keep the fractions over 81 until the end. Report a problem with this question