WAEC 2020 · Paper 1 · Q1

A binary operation ∗* is defined on the set of real numbers, R\mathbb{R}, by x∗y=x2−y2+xyx * y = x^2 - y^2 + xy, where x,y∈Rx, y \in \mathbb{R}. Evaluate (3)∗(2)(\sqrt{3}) * (\sqrt{2}).

Worked solution (try it first)
  1. Put x=3x = \sqrt{3} and y=2y = \sqrt{2} into the rule.
  2. The squares are x2=3x^2 = 3 and y2=2y^2 = 2.
  3. The product is xy=3×2=6xy = \sqrt{3} \times \sqrt{2} = \sqrt{6}.
  4. So (3)∗(2)=3−2+6(\sqrt{3}) * (\sqrt{2}) = 3 - 2 + \sqrt{6}
    =1+6= 1 + \sqrt{6}, option D.

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