WAEC 2020 · Paper 1 · Q33

The variables xx and yy are such that y=2x3−2x2−5x+5y = 2x^3 - 2x^2 - 5x + 5. Calculate the corresponding change in yy when xx changes from 2.00 to 2.05.

Worked solution (try it first)
  1. At x=2x = 2: y=16−8−10+5=3y = 16 - 8 - 10 + 5 = 3.
  2. At x=2.05x = 2.05: y=2(8.615125)−2(4.2025)−10.25+5y = 2(8.615125) - 2(4.2025) - 10.25 + 5
    =3.57525= 3.57525.
  3. The change is 3.57525−3=0.5753.57525 - 3 = 0.575, which is 0.58 to two decimal places, option A.

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