WAEC 2020 · Paper 1 · Q5

If (p+q10p−q)=(2108)\begin{pmatrix} p + q & 1 \\ 0 & p - q \end{pmatrix} = \begin{pmatrix} 2 & 1 \\ 0 & 8 \end{pmatrix}, find the values of pp and qq.

Worked solution (try it first)
  1. Equal matrices have equal entries in matching places: p+q=2p + q = 2 and p−q=8p - q = 8.
  2. Add the two equations: 2p=102p = 10, so p=5p = 5.
  3. Then q=2−5=−3q = 2 - 5 = -3.
  4. So p=5p = 5, q=−3q = -3, option B.

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