WAEC 2022 · Paper 1 · Q16

Kinematics & dynamics

A particle moving with a velocity of $5\text{ m s}^{-1}$ accelerates at $2\text{ m s}^{-2}$ . Find the distance it covers in 4 seconds.

Worked solution (try it first)

Use $s = ut + \frac12 at^2$ with $u = 5$ , $a = 2$ and $t = 4$ .
$ut = 5 \times 4 = 20$ and $\frac12 at^2 = \frac12 \times 2 \times 16$
$= 16$ .
So $s = 20 + 16 = 36$ m, option C.

Report a problem with this question